$6(9y-1)-10\cdot 5y-3y=22-4(2y-12)+8(y-6)$
Multiply the numbers: $ 10\cdot 5=50$$6(9y-1)-50y-3y=22-4(2y-12)+8(y-6)$
Add similar elements: $ -50y-3y=-53y$$6(9y-1)-53y=22-4(2y-12)+8(y-6)$
Expand $6(9y-1)-53y:{\quad}y-6$$y-6=22$
Add $6$ to both sides$y-6+6=22+6$
Simplify$y=28$