# Calculate: 3(x-2) >= (x+6)/(3)

## Expression: $3\left( x-2 \right) \geq \frac{ x+6 }{ 3 }$

Distribute $3$ through the parentheses

$3x-6 \geq \frac{ x+6 }{ 3 }$

Multiply both sides of the inequality by $3$

$9x-18 \geq x+6$

Move the variable to the left-hand side and change its sign

$9x-18-x \geq 6$

Move the constant to the right-hand side and change its sign

$9x-x \geq 6+18$

Collect like terms

$8x \geq 6+18$

$8x \geq 24$
Divide both sides of the inequality by $8$
\begin{align*}&x \geq 3 \\&\begin{array} { l }x \in \left[ 3, +\infty\right\rangle\end{array}\end{align*}