$=10r^{2}+\frac{12r^{2}+3r-13}{4r-3}$
Divide $ \frac{12r^{2}+3r-13}{4r-3}:{\quad}\frac{12r^{2}+3r-13}{4r-3}=3r+\frac{12r-13}{4r-3}$$=10r^{2}+3r+\frac{12r-13}{4r-3}$
Divide $ \frac{12r-13}{4r-3}:{\quad}\frac{12r-13}{4r-3}=3+\frac{-4}{4r-3}$$=10r^{2}+3r+3+\frac{-4}{4r-3}$
Simplify$=10r^{2}+3r+3-\frac{4}{4r-3}$