Solve for: /(5 r ^ 2-17 r-12) r ^ 2-r-12 =

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Expression: $\frac{3}{4}-\frac{0}{6}$

Apply rule $ \frac{0}{a}=0a\ne0$

$=\frac{3}{4}-0$

Apply rule $a+0=a$

$=\frac{3}{4}$

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