Solve for: log_{10}(x)+2=5

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Expression: $\log_{ 10 }({ x })+2=5$

Move the constant to the right-hand side and change its sign

$\log_{ 10 }({ x })=5-2$

Subtract the numbers

$\log_{ 10 }({ x })=3$

Convert the logarithm into exponential form using the fact that $\log_{ a }({ x })=b$ is equal to $x={a}^{b}$

$x={10}^{3}$

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