$\frac{ 1 }{ 7 }x+\frac{ 4 }{ 7 }=2x-6\left( 3-x \right)-5$
Distribute $-6$ through the parentheses$\frac{ 1 }{ 7 }x+\frac{ 4 }{ 7 }=2x-18+6x-5$
Collect like terms$\frac{ 1 }{ 7 }x+\frac{ 4 }{ 7 }=8x-18-5$
Calculate the difference$\frac{ 1 }{ 7 }x+\frac{ 4 }{ 7 }=8x-23$
Move the variable to the left-hand side and change its sign$\frac{ 1 }{ 7 }x+\frac{ 4 }{ 7 }-8x=-23$
Move the constant to the right-hand side and change its sign$\frac{ 1 }{ 7 }x-8x=-23-\frac{ 4 }{ 7 }$
Calculate the difference$-\frac{ 55 }{ 7 }x=-23-\frac{ 4 }{ 7 }$
Calculate the difference$-\frac{ 55 }{ 7 }x=-\frac{ 165 }{ 7 }$
Multiply both sides of the equation by $-\frac{ 7 }{ 55 }$$x=3$