Solve for: 2/(x-1)>= 1/(x+3)

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Expression: $\frac{2}{x-1}\ge \frac{1}{x+3}$

Rewrite in standard form

$\frac{x+7}{(x-1)(x+3)}\ge 0$

Identify the intervals

$-7\le x<-3\lor x>1$

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