Solve for: (-4 x+2) ^ 2-4

Expression: $$( - 4 x + 2 ) ^ { 2 } - 4$$

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(-4x+2\right)^{2}$.

$$16x^{2}-16x+4-4$$

Subtract $4$ from $4$ to get $0$.

$$16x^{2}-16x$$