Evaluate: (3x^2)/(x^2+8) > 0

Expression: $\frac{ 3{x}^{2} }{ {x}^{2}+8 } > 0$

The denominator is always positive, so determine when the numerator is greater than $0$

$3{x}^{2} > 0$

Since the left-hand side is always positive or $0$, the statement is true for any value of $x$, except when $3{x}^{2}=0$

$3{x}^{2}=0$

Solve the equation for $x$

$x=0$

The inequality is true for any value of $x$, except when $x=0$

$x$