Solve for: \lim_{x arrow 3} ((x^2+6x-14)/(3x-5))

Expression: $\lim_{x \rightarrow 3} \left(\frac{ {x}^{2}+6x-14 }{ 3x-5 }\right)$

$\frac{ {3}^{2}+6 \times 3-14 }{ 3 \times 3-5 }$

$\begin{align*}&\frac{ 13 }{ 4 } \\&\begin{array} { l }3 \frac{ 1 }{ 4 },& 3.25\end{array}\end{align*}$