$\begin{array} { l }\frac{ 1 }{ 3 }+\frac{ 4 }{ x }=\frac{ 5 }{ 6 },& x≠0\end{array}$
Move the constant to the right-hand side and change its sign$\frac{ 4 }{ x }=\frac{ 5 }{ 6 }-\frac{ 1 }{ 3 }$
Subtract the fractions$\frac{ 4 }{ x }=\frac{ 1 }{ 2 }$
Simplify the equation using cross-multiplication$8=x$
Swap the sides of the equation$\begin{array} { l }x=8,& x≠0\end{array}$
Check if the solution is in the defined range$x=8$