Solve for: 3 * 4-((-2)^2-4)^3

Expression: $3 \times 4-{\left( {\left( -2 \right)}^{2}-4 \right)}^{3}$

Multiply the numbers

$12-{\left( {\left( -2 \right)}^{2}-4 \right)}^{3}$

Evaluate the power

$12-{\left( 4-4 \right)}^{3}$

The sum of two opposites equals $0$

$12-{0}^{3}$

$0$ raised to any positive power equals $0$

$12-0$

Removing $0$ doesn't change the value, so remove it from the expression

$12$