$=\frac{\frac{x^{2}-9x+10}{x(x-2)}}{\frac{3}{x}+1}$
Join $\frac{3}{x}+1:{\quad}\frac{x+3}{x}$$=\frac{\frac{x^{2}-9x+10}{x(x-2)}}{\frac{x+3}{x}}$
Apply the fraction rule $\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}$$=\frac{(x^{2}-9x+10)x}{x(x-2)(x+3)}$
Cancel the common factor: $ x$$=\frac{x^{2}-9x+10}{(x-2)(x+3)}$