${t}^{2}-10t+9=0$
Solve the equation for $t$$\begin{array} { l }t=1,\\t=9\end{array}$
Substitute back $t={x}^{2}$$\begin{array} { l }{x}^{2}=1,\\{x}^{2}=9\end{array}$
Solve the equation for $x$$\begin{array} { l }x=-1,\\x=1,\\{x}^{2}=9\end{array}$
Solve the equation for $x$$\begin{array} { l }x=-1,\\x=1,\\x=-3,\\x=3\end{array}$
The equation has $4$ solutions$\begin{array} { l }x_1=-3,& x_2=-1,& x_3=1,& x_4=3\end{array}$