Solve for: (-6x^2p^3) * (8y^3x^2)

Expression: $\left( -6{x}^{2}{p}^{3} \right) \times \left( 8{y}^{3}{x}^{2} \right)$

Use the commutative property to reorder the terms

$\left( -6{p}^{3}{x}^{2} \right) \times \left( 8{y}^{3}{x}^{2} \right)$

Use the commutative property to reorder the terms

$\left( -6{p}^{3}{x}^{2} \right) \times \left( 8{x}^{2}{y}^{3} \right)$

Multiplying a negative and a positive equals a negative: $\left( - \right) \times \left( + \right)=\left( - \right)$

$-6{p}^{3}{x}^{2} \times 8{x}^{2}{y}^{3}$

Calculate the product

$-48{p}^{3}{x}^{4}{y}^{3}$