${x}^{2}-14+5=0$
Calculate the sum${x}^{2}-9=0$
Identify the coefficients $a$, $b$ and $c$ of the quadratic equation$\begin{array} { l }a=1,& b=0,& c=-9\end{array}$
Substitute $a=1$, $b=0$ and $c=-9$ into the quadratic formula $x=\frac{ -b\pm\sqrt{ {b}^{2}-4ac } }{ 2a }$$x=\frac{ -0\pm\sqrt{ {0}^{2}-4 \times 1 \times \left( -9 \right) } }{ 2 \times 1 }$
Removing $0$ doesn't change the value, so remove it from the expression$x=\frac{ \sqrt{ {0}^{2}-4 \times 1 \times \left( -9 \right) } }{ 2 \times 1 }$
Any expression multiplied by $1$ remains the same$x=\frac{ \sqrt{ {0}^{2}-4 \times \left( -9 \right) } }{ 2 \times 1 }$
Any expression multiplied by $1$ remains the same$x=\frac{ \sqrt{ {0}^{2}-4 \times \left( -9 \right) } }{ 2 }$
$0$ raised to any positive power equals $0$$x=\frac{ \sqrt{ 0-4 \times \left( -9 \right) } }{ 2 }$
Multiply the numbers$x=\frac{ \sqrt{ 0+36 } }{ 2 }$
Removing $0$ doesn't change the value, so remove it from the expression$x=\frac{ \sqrt{ 36 } }{ 2 }$
Evaluate the square root$x=\frac{ 6 }{ 2 }$
Write the solutions, one with a $+$ sign and one with a $-$ sign$\begin{array} { l }x=\frac{ 6 }{ 2 },\\x=\frac{ -6 }{ 2 }\end{array}$
Cancel out the common factor $2$$\begin{array} { l }x=3,\\x=\frac{ -6 }{ 2 }\end{array}$
Cancel out the common factor $2$$\begin{array} { l }x=3,\\x=-3\end{array}$
The equation has $2$ solutions$\begin{array} { l }x_1=-3,& x_2=3\end{array}$