Solve for: (4x^2+x-8)/(x+2)

Expression: $\frac{4x^{2}+x-8}{x+2}$

Divide $ \frac{4x^{2}+x-8}{x+2}:{\quad}\frac{4x^{2}+x-8}{x+2}=4x+\frac{-7x-8}{x+2}$

$=4x+\frac{-7x-8}{x+2}$

Divide $ \frac{-7x-8}{x+2}:{\quad}\frac{-7x-8}{x+2}=-7+\frac{6}{x+2}$

$=4x-7+\frac{6}{x+2}$