Calculate: (-(x^4)/3+3y)(x^2-xy+y^2)

Expression: $(-\frac{x^{4}}{3}+3y)(x^{2}-xy+y^{2})$

Join $-\frac{x^{4}}{3}+3y:{\quad}\frac{9y-x^{4}}{3}$

$=\frac{9y-x^{4}}{3}(x^{2}-xy+y^{2})$

Apply the fraction rule $a\cdot\frac{b}{c}=\frac{a\cdot b}{c}$

$=\frac{(9y-x^{4})(x^{2}-xy+y^{2})}{3}$