Calculate: sqrt(2x-1)=x-3

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Expression: $\sqrt{2x-1}=x-3$

Square both sides $:{\quad}2x-1=x^{2}-6x+9$

$2x-1=x^{2}-6x+9$

Solve $ 2x-1=x^{2}-6x+9:{\quad}x=4+\sqrt{6},x=4-\sqrt{6}$

$x=4+\sqrt{6},x=4-\sqrt{6}$

The solution is

$x=4+\sqrt{6}$

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