$2\left( x-5 \right)+3\left( 3x-1 \right)=24$
Distribute $2$ through the parentheses$2x-10+3\left( 3x-1 \right)=24$
Distribute $3$ through the parentheses$2x-10+9x-3=24$
Collect like terms$11x-10-3=24$
Calculate the difference$11x-13=24$
Move the constant to the right-hand side and change its sign$11x=24+13$
Add the numbers$11x=37$
Divide both sides of the equation by $11$$\begin{align*}&x=\frac{ 37 }{ 11 } \\&\begin{array} { l }x=3 \frac{ 4 }{ 11 },& x=3.\overset{ \cdot }{ 3 } \overset{ \cdot }{ 6 } \end{array}\end{align*}$