$-8x \times 7{x}^{2}-8x \times \left( -2x \right)-8x \times 5$
Calculate the product$-56{x}^{3}-8x \times \left( -2x \right)-8x \times 5$
Multiplying two negatives equals a positive: $\left( - \right) \times \left( - \right)=\left( + \right)$$-56{x}^{3}+8x \times 2x-8x \times 5$
Calculate the product$-56{x}^{3}+16{x}^{2}-8x \times 5$
Calculate the product$-56{x}^{3}+16{x}^{2}-40x$