Solve for: 8(3x+1)=32

Expression: $8\left( 3x+1 \right)=32$

Divide both sides of the equation by $8$

$3x+1=4$

Move the constant to the right-hand side and change its sign

$3x=4-1$

Subtract the numbers

$3x=3$

Divide both sides of the equation by $3$

$x=1$