Solve for: e^{x+1}=1

Expression: ${e}^{x+1}=1$

Write the number in exponential form with the base of $e$

${e}^{x+1}={e}^{0}$

Since the bases are the same, set the exponents equal

$x+1=0$

Move the constant to the right-hand side and change its sign

$x=-1$

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