Solve for: (3x^4-8x^3+9x-29)/(3x-8)

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Expression: $\frac{3x^{4}-8x^{3}+9x-29}{3x-8}$

Divide $ \frac{3x^{4}-8x^{3}+9x-29}{3x-8}:{\quad}\frac{3x^{4}-8x^{3}+9x-29}{3x-8}=x^{3}+\frac{9x-29}{3x-8}$

$=x^{3}+\frac{9x-29}{3x-8}$

Divide $ \frac{9x-29}{3x-8}:{\quad}\frac{9x-29}{3x-8}=3+\frac{-5}{3x-8}$

$=x^{3}+3+\frac{-5}{3x-8}$

Simplify

$=x^{3}+3-\frac{5}{3x-8}$

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