$$\frac{6+1}{6}\times \left(\frac{2\times 7+2}{7}\right)$$
Add $6$ and $1$ to get $7$.$$\frac{7}{6}\times \left(\frac{2\times 7+2}{7}\right)$$
Multiply $2$ and $7$ to get $14$.$$\frac{7}{6}\times \left(\frac{14+2}{7}\right)$$
Add $14$ and $2$ to get $16$.$$\frac{7}{6}\times \left(\frac{16}{7}\right)$$
Multiply $\frac{7}{6}$ times $\frac{16}{7}$ by multiplying numerator times numerator and denominator times denominator.$$\frac{7\times 16}{6\times 7}$$
Cancel out $7$ in both numerator and denominator.$$\frac{16}{6}$$
Reduce the fraction $\frac{16}{6}$ to lowest terms by extracting and canceling out $2$.$$\frac{8}{3}$$