Solve for: 1/5 ⁢(x-2)-(2⁢x-3) = 2/3 ⁢(4⁢x+1)-1/6 ⁢(2⁢x+7)

Expression: $\frac{1}{5}⁢\left(x - 2\right) - \left(2⁢x - 3\right) = \frac{2}{3}⁢\left(4⁢x + 1\right) - \frac{1}{6}⁢\left(2⁢x + 7\right)$

$\begin{matrix} x = \frac{3}{4} \\ \end{matrix}$