Solve for: (2n-6)+(n-6)+n=45

Expression: $\left( 2n-6 \right)+\left( n-6 \right)+n=45$

Remove unnecessary parentheses

$2n-6+\left( n-6 \right)+n=45$

When there is a $+$ in front of an expression in parentheses, the expression remains the same

$2n-6+n-6+n=45$

Collect like terms

$4n-6-6=45$

Calculate the difference

$4n-12=45$

Move the constant to the right-hand side and change its sign

$4n=45+12$

Add the numbers

$4n=57$

Divide both sides of the equation by $4$

$\begin{align*}&n=\frac{ 57 }{ 4 } \\&\begin{array} { l }n=14 \frac{ 1 }{ 4 },& n=14.25\end{array}\end{align*}$