$2 \times |h|=8+3$
Add the numbers$2 \times |h|=11$
Divide both sides of the equation by $2$$|h|=\frac{ 11 }{ 2 }$
Use the absolute value definition to rewrite the absolute value equation as two separate equations$\begin{array} { l }h=\frac{ 11 }{ 2 },\\h=-\frac{ 11 }{ 2 }\end{array}$
The equation has $2$ solutions$\begin{align*}&\begin{array} { l }h_1=-\frac{ 11 }{ 2 },& h_2=\frac{ 11 }{ 2 }\end{array} \\&\begin{array} { l }h_1=-5.5,& h_2=5.5\end{array}\end{align*}$