Solve for: 2 \times |h|-3=8

Expression: $2 \times |h|-3=8$

Move the constant to the right-hand side and change its sign

$2 \times |h|=8+3$

Add the numbers

$2 \times |h|=11$

Divide both sides of the equation by $2$

$|h|=\frac{ 11 }{ 2 }$

Use the absolute value definition to rewrite the absolute value equation as two separate equations

$\begin{array} { l }h=\frac{ 11 }{ 2 },\\h=-\frac{ 11 }{ 2 }\end{array}$

The equation has $2$ solutions

$\begin{align*}&\begin{array} { l }h_1=-\frac{ 11 }{ 2 },& h_2=\frac{ 11 }{ 2 }\end{array} \\&\begin{array} { l }h_1=-5.5,& h_2=5.5\end{array}\end{align*}$