# Evaluate: 24(y-1)=-6(5+y)

## Expression: $24\left( y-1 \right)=-6\left( 5+y \right)$

Rewrite the equation in slope-intercept form

$y=-\frac{ 1 }{ 5 }$

A term with $x$ is missing, which means that this term has the coefficient $0$

$y=0x-\frac{ 1 }{ 5 }$

Subtracting is the same as adding the opposite

$y=0x+\left( -\frac{ 1 }{ 5 } \right)$

Since the equation is written in slope-intercept form, $y=mx+b$, identify the slope of the line as the coefficient next to the variable $x$

$\begin{array} { l }y=0x+\left( -\frac{ 1 }{ 5 } \right),& m=0\end{array}$

Identify the $y$-intercept of the line as the constant term

$\begin{array} { l }y=0x+\left( -\frac{ 1 }{ 5 } \right),& m=0,& b=-\frac{ 1 }{ 5 }\end{array}$

The slope of the line is $m=0$ and the $y$-intercept is $b=-\frac{ 1 }{ 5 }$

$\begin{array} { l }m=0,& b=-\frac{ 1 }{ 5 }\end{array}$

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