# Solve for: -3x > 3

## Expression: $-3x > 3$

Divide both sides of the inequality by $-3$ and flip the inequality sign

$-3x\div\left( -3 \right) < 3\div\left( -3 \right)$

Any expression divided by itself equals $1$

$x < 3\div\left( -3 \right)$

Dividing a positive and a negative equals a negative: $\left( + \right)\div\left( - \right)=\left( - \right)$

$x < -3\div3$

Calculate the quotient

\begin{align*}&x < -1 \\&\begin{array} { l }x \in \langle-\infty, -1\rangle\end{array}\end{align*}

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