Evaluate: {\text{begin}array l x-2y=0 } y=2x-3\text{end}array .

Expression: $\left\{\begin{array} { l } x-2y=0 \\ y=2x-3\end{array} \right.$

Substitute the given value of $y$ into the equation $x-2y=0$

$x-2\left( 2x-3 \right)=0$

Solve the equation for $x$

$x=2$

Substitute the given value of $x$ into the equation $y=2x-3$

$y=2 \times 2-3$

Solve the equation for $y$

$y=1$

The possible solution of the system is the ordered pair $\left( x, y\right)$

$\left( x, y\right)=\left( 2, 1\right)$

Check if the given ordered pair is the solution of the system of equations

$\left\{\begin{array} { l } 2-2 \times 1=0 \\ 1=2 \times 2-3\end{array} \right.$

Simplify the equalities

$\left\{\begin{array} { l } 0=0 \\ 1=1\end{array} \right.$

Since all of the equalities are true, the ordered pair is the solution of the system

$\left( x, y\right)=\left( 2, 1\right)$