$x-2\left( 2x-3 \right)=0$
Solve the equation for $x$$x=2$
Substitute the given value of $x$ into the equation $y=2x-3$$y=2 \times 2-3$
Solve the equation for $y$$y=1$
The possible solution of the system is the ordered pair $\left( x, y\right)$$\left( x, y\right)=\left( 2, 1\right)$
Check if the given ordered pair is the solution of the system of equations$\left\{\begin{array} { l } 2-2 \times 1=0 \\ 1=2 \times 2-3\end{array} \right.$
Simplify the equalities$\left\{\begin{array} { l } 0=0 \\ 1=1\end{array} \right.$
Since all of the equalities are true, the ordered pair is the solution of the system$\left( x, y\right)=\left( 2, 1\right)$