# Solve for: 6 (1)/(3)+4 (3)/(4)+3 (7)/(12)

## Expression: $6 \frac{ 1 }{ 3 }+4 \frac{ 3 }{ 4 }+3 \frac{ 7 }{ 12 }$

Add the whole numbers and fractional parts of the mixed numbers separately

$\left( 6+4+3 \right)+\left( \frac{ 1 }{ 3 }+\frac{ 3 }{ 4 }+\frac{ 7 }{ 12 } \right)$

Calculate the sum of the positive numbers

$13+\left( \frac{ 1 }{ 3 }+\frac{ 3 }{ 4 }+\frac{ 7 }{ 12 } \right)$

Calculate the sum

$13+\frac{ 5 }{ 3 }$

Convert the improper fraction into a mixed number

$13+1 \frac{ 2 }{ 3 }$

Write the mixed number as a sum of the whole number and the fractional part

$13+1+\frac{ 2 }{ 3 }$

$14+\frac{ 2 }{ 3 }$
\begin{align*}&14 \frac{ 2 }{ 3 } \\&\begin{array} { l }\frac{ 44 }{ 3 },& 14.\overset{ \cdot }{ 6 } \end{array}\end{align*}