Solve for: 8 (4 k-4) =-5 k-32

Expression: $$8 ( 4 k - 4 ) = - 5 k - 32$$

Use the distributive property to multiply $8$ by $4k-4$.

$$32k-32=-5k-32$$

Add $5k$ to both sides.

$$32k-32+5k=-32$$

Combine $32k$ and $5k$ to get $37k$.

$$37k-32=-32$$

Add $32$ to both sides.

$$37k=-32+32$$

Add $-32$ and $32$ to get $0$.

$$37k=0$$

Product of two numbers is equal to $0$ if at least one of them is $0$. Since $37$ is not equal to $0$, $k$ must be equal to $0$.

$$k=0$$