$$8-3\left(2-\frac{4^{2}}{8}\times 2\right)$$
Calculate $4$ to the power of $2$ and get $16$.$$8-3\left(2-\frac{16}{8}\times 2\right)$$
Divide $16$ by $8$ to get $2$.$$8-3\left(2-2\times 2\right)$$
Multiply $2$ and $2$ to get $4$.$$8-3\left(2-4\right)$$
Subtract $4$ from $2$ to get $-2$.$$8-3\left(-2\right)$$
Multiply $3$ and $-2$ to get $-6$.$$8-\left(-6\right)$$
The opposite of $-6$ is $6$.$$8+6$$
Add $8$ and $6$ to get $14$.$$14$$