$$\frac{\left(3\times 4+1\right)\times 8}{4\left(2\times 8+3\right)}$$
Cancel out $4$ in both numerator and denominator.$$\frac{2\left(1+3\times 4\right)}{3+2\times 8}$$
Multiply $3$ and $4$ to get $12$.$$\frac{2\left(1+12\right)}{3+2\times 8}$$
Add $1$ and $12$ to get $13$.$$\frac{2\times 13}{3+2\times 8}$$
Multiply $2$ and $13$ to get $26$.$$\frac{26}{3+2\times 8}$$
Multiply $2$ and $8$ to get $16$.$$\frac{26}{3+16}$$
Add $3$ and $16$ to get $19$.$$\frac{26}{19}$$