$3 \times |2u+8|=-8+38$
Calculate the sum$3 \times |2u+8|=30$
Divide both sides of the equation by $3$$|2u+8|=10$
Use the absolute value definition to rewrite the absolute value equation as two separate equations$\begin{array} { l }2u+8=10,\\2u+8=-10\end{array}$
Solve the equation for $u$$\begin{array} { l }u=1,\\2u+8=-10\end{array}$
Solve the equation for $u$$\begin{array} { l }u=1,\\u=-9\end{array}$
The equation has $2$ solutions$\begin{array} { l }u_1=-9,& u_2=1\end{array}$