Calculate: 3 \times |2u+8|-38=-8

Expression: $3 \times |2u+8|-38=-8$

Move the constant to the right-hand side and change its sign

$3 \times |2u+8|=-8+38$

Calculate the sum

$3 \times |2u+8|=30$

Divide both sides of the equation by $3$

$|2u+8|=10$

Use the absolute value definition to rewrite the absolute value equation as two separate equations

$\begin{array} { l }2u+8=10,\\2u+8=-10\end{array}$

Solve the equation for $u$

$\begin{array} { l }u=1,\\2u+8=-10\end{array}$

Solve the equation for $u$

$\begin{array} { l }u=1,\\u=-9\end{array}$

The equation has $2$ solutions

$\begin{array} { l }u_1=-9,& u_2=1\end{array}$