Solve for: 12(x-3)=11-(x-5)

Expression: $12\left( x-3 \right)=11-\left( x-5 \right)$

Distribute $12$ through the parentheses

$12x-36=11-\left( x-5 \right)$

When there is a $-$ in front of an expression in parentheses, change the sign of each term of the expression and remove the parentheses

$12x-36=11-x+5$

Add the numbers

$12x-36=16-x$

Move the variable to the left-hand side and change its sign

$12x-36+x=16$

Move the constant to the right-hand side and change its sign

$12x+x=16+36$

Collect like terms

$13x=16+36$

Add the numbers

$13x=52$

Divide both sides of the equation by $13$

$x=4$