Solve for: 5 \times |2r+3|-5=0

Expression: $5 \times |2r+3|-5=0$

Move the constant to the right-hand side and change its sign

$5 \times |2r+3|=5$

Divide both sides of the equation by $5$

$|2r+3|=1$

Use the absolute value definition to rewrite the absolute value equation as two separate equations

$\begin{array} { l }2r+3=1,\\2r+3=-1\end{array}$

Solve the equation for $r$

$\begin{array} { l }r=-1,\\2r+3=-1\end{array}$

Solve the equation for $r$

$\begin{array} { l }r=-1,\\r=-2\end{array}$

The equation has $2$ solutions

$\begin{array} { l }r_1=-2,& r_2=-1\end{array}$