Solve for: 100\div(2+3)^2-8\div2

Expression: $100\div{\left( 2+3 \right)}^{2}-8\div2$

Add the numbers

$100\div{5}^{2}-8\div2$

Divide the numbers

$100\div{5}^{2}-4$

Write the division as a fraction

$\frac{ 100 }{ {5}^{2} }-4$

Evaluate the power

$\frac{ 100 }{ 25 }-4$

Cancel out the common factor $25$

$4-4$

The sum of two opposites equals $0$

$0$