Solve for: 2K-3(4-K)=3K+4

Expression: $2K-3\left( 4-K \right)=3K+4$

Distribute $-3$ through the parentheses

$2K-12+3K=3K+4$

Cancel equal terms on both sides of the equation

$2K-12=4$

Move the constant to the right-hand side and change its sign

$2K=4+12$

Add the numbers

$2K=16$

Divide both sides of the equation by $2$

$K=8$