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Solve for: 2K-3(4-K)=3K+4
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Solve for: 2K-3(4-K)=3K+4
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Expression: $2K-3\left( 4-K \right)=3K+4$
Distribute $-3$ through the parentheses
$2K-12+3K=3K+4$
Cancel equal terms on both sides of the equation
$2K-12=4$
Move the constant to the right-hand side and change its sign
$2K=4+12$
Add the numbers
$2K=16$
Divide both sides of the equation by $2$
$K=8$
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