$\begin{array} { l }a=8,& b=-2,& c=1\end{array}$
Evaluate the discriminant by substituting $a=8$, $b=-2$ and $c=1$ into the expression ${b}^{2}-4ac$${\left( -2 \right)}^{2}-4 \times 8 \times 1$
Simplify the expression$-28$
The discriminant is less than $0$, so the quadratic equation has no real solutions$\textnormal{No real solutions}$