${10}^{x+1}=99+1$
Add the numbers${10}^{x+1}=100$
Write the number in exponential form with the base of $10$${10}^{x+1}={10}^{2}$
Since the bases are the same, set the exponents equal$x+1=2$
Move the constant to the right-hand side and change its sign$x=2-1$
Subtract the numbers$x=1$