Calculate: log_{10}(x)+log_{10}(x-1)=log_{10}(3x+12)
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- Calculate: log_{10}(x)+log_{10}(x-1)=log_{10}(3x+12)
Expression: $\log_{10}(x)+\log_{10}(x-1)=\log_{10}(3x+12)$
Apply log rules $x(x-1)=3x+12$
Solve $ x(x-1)=3x+12:{\quad}x=6,x=-2$$x=6,x=-2$
The solution is $x=6$