$$\frac{-\frac{30+4}{5}}{\frac{2\times 3+1}{3}}$$
Add $30$ and $4$ to get $34$.$$\frac{-\frac{34}{5}}{\frac{2\times 3+1}{3}}$$
Multiply $2$ and $3$ to get $6$.$$\frac{-\frac{34}{5}}{\frac{6+1}{3}}$$
Add $6$ and $1$ to get $7$.$$\frac{-\frac{34}{5}}{\frac{7}{3}}$$
Divide $-\frac{34}{5}$ by $\frac{7}{3}$ by multiplying $-\frac{34}{5}$ by the reciprocal of $\frac{7}{3}$.$$-\frac{34}{5}\times \left(\frac{3}{7}\right)$$
Multiply $-\frac{34}{5}$ times $\frac{3}{7}$ by multiplying numerator times numerator and denominator times denominator.$$\frac{-34\times 3}{5\times 7}$$
Do the multiplications in the fraction $\frac{-34\times 3}{5\times 7}$.$$\frac{-102}{35}$$
Fraction $\frac{-102}{35}$ can be rewritten as $-\frac{102}{35}$ by extracting the negative sign.$$-\frac{102}{35}$$